9d^2-24d+7=0

Solution for 9d^2-24d+7=0 equation:

9d^2-24d+7=0

a = 9; b = -24; c = +7;
Δ = b2-4ac
Δ = -242-4·9·7
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-18}{2*9}=\frac{6}{18}
=1/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+18}{2*9}=\frac{42}{18}
=2+1/3
$